1. A total of Rs. 50000 is to be distributed among 200 persons as prizes. The prizes are comprised are of either
Rs.500 or Rs. 100 . Find the number of each type of prizes. 2. The denominator of a rational number is greater than its numerator by 3. If 3 is subtracted from thenumerator and 2 is added to its denominator , the new number becomes 1/5. Find the original number
Answers
Answered by
1
let x rs500 prizes are there.200-x rs100 prizes
500x +200-x*100=50000
500x+20000-100x=50000
400x=30000
x=75
500x +200-x*100=50000
500x+20000-100x=50000
400x=30000
x=75
Answered by
1
Let 500 Rs prizes be x & 100 Rs prizes be y
50000 = 500x + 100y => 500 = 5x + y
x + y = 200 (total no. of prizes)
Solve, X = 75 & y = 125
2. D = N + 3
(N - 3)/(D+2) = 1/5
=> 5D - 30 = D + 2
=> D = 8 & N = 5 => number is 5/8
50000 = 500x + 100y => 500 = 5x + y
x + y = 200 (total no. of prizes)
Solve, X = 75 & y = 125
2. D = N + 3
(N - 3)/(D+2) = 1/5
=> 5D - 30 = D + 2
=> D = 8 & N = 5 => number is 5/8
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