1.A town has population of 20,000 in 1995. In one year i.e. by 1996 it increased by 10%. Next year i.e. in 1997, it decreased by 20%. The next year in 1998 there was an increase of 50%. What is the population at end of 1998? *
Answers
Answer:
Answer:
Population at the end of the two years is 253000 .
Step-by-step explanation:
As given
The present population of a town is 200000.
Its population increases by 10% in the first year .
10% is written in the decimal form
= 0.10
Population increases by 10% = 0.10 × Present population
= 0.10 × 200000
= 20000
Thus
Popluation in the first year = Present population + Population increases by 10% .
= 200000 + 20000
= 220000
Thus the population in the first year = 220000
As 15% is written in the decimal form
= 0.15
increases in population by 15% = 0.15 × Population in the first year
= 0.15 × 220000
= 33000
thus
Population in the second year = Population in the first year + increases in population by 15% .
= 220000 + 33000
= 253000
Therefore the population at the end of the two years is 253000
Answer:
26400
Step-by-step explanation:
1996= 10/100×20000
=> 2000
Total Population In 1996 =22000
1997 =20/100×22000=4400
Total Population In 1997 = 17600
1998=50/100×17600
=> 8800
Total Population In 1998 is 26400