Question

1. A train starting from rest attains a velocity of 72 km h–1

in 5 minutes. Assuming that the acceleration is

uniform, find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity.​

Answer 1

Answer:

Explanation:

(i)

By Newton's first EQ of MOTION

v = u +at

v = 72 km/h = 20m/s

And t = 5min = 300sec

20 = 0+ a*300

a = 1/15 m/s^2

(ii)

By Newton's third eq of MOTION

v^2 - u^2 = 2as

20^2 - 0 = 2*1/15*s

400*15/2 = s

3000m = s

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