Math, asked by Anonymous, 8 months ago

factorise the following identities. 1).16y²-16y+4

Answers

Answered by ShivajiMaharaj45
1

Step-by-step explanation:

\sf 16 {y}^{2} - 16y + 4

\\

\sf = {4y}^{2} - 2 × 4 y × 2 + {2}^{2}

\\

\sf {(4y - 2 )}^{2}

\\

\sf ( 4y - 2 )( 4y - 2 )

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Answered by manaiskaran
1

Answer:

4(4y square -4y +1)=0

4y square -4 y+1=0

4y^ -2 y -2 y +1=0

2y(2y -1)-1(2y -1)=0

(2y -1)(2y-1)=0

2y-1=0

y=1/2,1/2

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