Physics, asked by danger47, 1 year ago

1. A transparent cube of 15 cm edge contains a small air bubble. Its apparent depth when viewed through
one face is 6 cm and when viewed through the opposite face is 4 cm. Then the refractive index of the
material of the cube is :
(A) 2.0 (B) 1.5 (C) 1.6 (D) 2.5

Answers

Answered by kvnmurty
163
Real depth / apparent depth = refractive index

   h1 / 6 cm = μ    =>  h1 = 6 μ  cm

   h2 / 4cm =  μ    =>  h2 = 4 μ  cm

        h1 + h2 =  15 cm = 10 μ    =>    μ = 1.5 cm

The bubble is in the middle of the width of the cube.  So real depth from h1 one side face is equal to (15-h1) of the real depth from the opposite face.


kvnmurty: click on thank you link pls
Answered by Manulal857
6

Answer: Hey Buddy here's ur answer

Real depth / apparent depth = refractive index

h1 / 6 cm = μ => h1 = 6 μ cm

h2 / 4cm = μ => h2 = 4 μ cm

h1 + h2 = 15 cm = 10 μ => μ = 1.5 cm

The bubble is in the middle of the width of the cube. So real depth from h1 one side face is equal to (15-h1) of the real depth from the opposite face.

Explanation:

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