1) A transversal intersect two parallel lines such that the ratio between the interior
angles on one of its sides is 3: 7 then, the measure of the smaller angles is .....
A)54°
B) 126°
C)30°
D)70°
Answers
Answered by
3
Answer:
As you said they are internal angles on one side of transversal
therefore their sum will be 180. Let the common ratio be x.
Step-by-step explanation:
3x+7x=180°
10x=180°
x=180÷10
x=18°
Therefore, 3x= 3 × 18=54°
And, 7x=7×18=126°
Smaller is 54° Hence answer is 54° or A.
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