Math, asked by vaishalianekar14, 7 months ago

1) A transversal intersect two parallel lines such that the ratio between the interior
angles on one of its sides is 3: 7 then, the measure of the smaller angles is .....
A)54°
B) 126°
C)30°
D)70°​

Answers

Answered by AdhvikDogra
3

Answer:

As you said they are internal angles on one side of transversal

therefore their sum will be 180. Let the common ratio be x.

Step-by-step explanation:

3x+7x=180°

10x=180°

x=180÷10

x=18°

Therefore, 3x= 3 × 18=54°

And, 7x=7×18=126°

Smaller is 54° Hence answer is 54° or A.

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