Question

1) A tuning fork has a frequency of 250 Hz. What is the time period of vibration?
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Answer 1

frequency ( f ) = 250Hz

time period ( T ) = ?

now, Frequency = 1/T

T = 1/250 = 0.004 seconds

hence the time period of vibration is 0.004s

Answer 2

Answer:

0.004

HOPE IT HELPS @_@

Explanation:

Given :

Frequency = 250 Hz

Hence,

Frequency = 1 / time period

.'. 250 Hz = 1 / time period

.'. Time period = 1 / 250

.'. Time = 0.004

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