Question

1.
A tuning fork produces 4 beats/sec. with another
tuning fork B of frequency 288 Hz. If fork is loaded
with little wax no. of beats per sec decreases. The
frequency of the fork A, before loading is
(1) 290 Hz
(2) 288 Hz
(3) 292 Hz
(4) 284 Hz​

Answer 1

Answer- 252 Hz

● Explaination-

# Given-

n1 = 256 Hz

n2 = unknown

b1 = 4 Hz

b2 = 6 Hz

# Solution-

Initially,

n2 = n1 + b or n1 - b

n2 = 256 + 4 or 256 - 4

n2 = 260 Hz or 252 Hz

After putting wax, frequency of tuning fork will decrease. n2' < n2 .

(I) Taking n2 = 260 ,

n2' = 256 + 6 = 262 Hz

Here, n2' > n2 which is not the case in added wax.

(II) Taking n2 = 252 Hz,

n2' = 256 - 6 = 250 Hz

Here, n2' < n2 ,which is the case for wax adding.

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Answer 2

Explanation:

292 Hz is the answer DUDE