1. A vehicle has a mass of 1500 kg. What must be the force between the vehicle and the
road if the vehicle is to be stopped with a negative acceleration of 1.7 ms 2?
(Ans:--2550 N in a direction opposite to that of the motion of the vehicle) (AS)
Answers
Given :
- Mass of a vehicle, m = 1500 kg
- Acceleration, a = - 1.7 m/s²
To find :
- Force between the vehicle and the road, F
According to the question,
➞ Force = Mass × Acceleration
Or,
➞ F = ma
➞ F = 1500 × (- 1.7)
➞ F = - 2550
- So,the force between the vehicle and the road is - 2550 Newton.
Note : Negative signs means that the force is acting on opposite direction.
___________________
Retardation ;
Negative acceleration is known as retardation.
- SI unit is m/s²
More formulas :
Newton's first equation of motion :
- v = u + at
Newton's second equation of motion :
- s = ut + ½ at²
Newton's third equation of motion :
- v² = u² + 2as
Answer:
Given :-
- A vehicle has a mass of 1500 kg. The vehicle is to be stopped with a negetive acceleration of - 1.7 m/s².
To Find :-
- What is the force between the vehicle and the road.
Formula Used :-
By using second law of motion we know that,
★ Force = Mass × Acceleration ★
Solution :-
Given :
- Mass = 1500 kg
- Acceleration = - 1.7 m/s²
According to the question by using the formula we get,
⇒ F = ma
⇒ F = 1500 × (- 1.7)
➠ F = - 2550 N
∴ The force between the vehicle and the road is - 2550 N .
✯ Extra Information ✯
⍟︎ Newton's 1st Law of Motion :-
- Newton's 1st law states that the body at rest or uniform motion will be continued to be at rest or uniform motion untill and unless a net force acts on it.
⍟︎ Newton's 2nd Law of Motion :-
- Newton's 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force in the same direction.
⍟︎ Newton's 3rd Law of Motion :-
- Newton's 3rd law of motion states that for every action there is an equal and opposite reaction.
✦ Important Formula ✦
⋆ First equation of motion :
↦ v = u + at
⋆ Second equation of motion :
↦ s = ut + ½ at²
⋆ Third equation of motion :
↦ v² = u² + 2as