Question

1) A vehide has a mass of 1550 kg. what must be the force between the vehicle and road if the
vehicle is to be stopped with an acceleration of 1.8 m/s2
2) An object of mass 120 kg is accelerated uniformly from a velocity of 5 m/s to 10 m/s in 9
seconds. Calculate initial and final momentum of the object. Also find the magnitude of force
exerted on the object.
3) Two objects of mass 100 gm. & 200 gm. are moving along the same line and direction with
velocity of 10 m/s and 15 m/s. They collide and after collision, the first object moves at a velocity
of 1.5 m/s. Determine the velocity of the 2nd object.​

Answer 1

Answer:

Explanation:

1.Given

Mass = 1550 kg

Acceleration = 1.8 m/s^2

Force = ?

We know the formula that,

Force = Mass* Acceleration

Using the formula we will substitute the values, so

Force = 1550 * 1.8

Force = 2790 Newton

2. Given

Mass = 120 kg

Initial Velocity = 5m/s

Final velocity = 10m/s

Time = 9 seconds

We know the formula

Momentum = Mass* Velocity

Initial momentum will be Mass* Initial Velocity

So placing the values,

Initial Momentum = 120*5

Initial Momentum = 600 kgm/s

Similarly Final Momentum will be

Final Momentum = 120*10

Final Momentum = 1200 kgm/s

Now to find the force we need to find acceleration first.

Acceleration = v-u/t , where v is final velocity and u is initial velocity and t is time.

Placing the values,

a = 10-5/9

a = 5/9 m/s^2

Now force Will be Mass*Acceleration

Force = 5/9*120

Force = 66.66 Newton( approx.)

3. Given

Given,

Mass1 = 100gm = 0.1 kg

Mass2 = 200gm = 0.2 kg

Initial Velocity 1 = 10m/s

Initial Velocity 2 = 15m/s

Final Velocity 1= 1.5m/s

Final Velocity 2 = ?

We know that, m1u1+m2u2=m1v1+m2v2 ( m= mass, v = Final vel. , u = initial vel.)

Placing the values,

(0.1*10)+(0.2*15)=(0.1*1.5)+(0.2*v2)

1+0.3 = 0.15+0.2v2

1.3 - 0.15 = 0.2*v2

1.15/0.2 = v2

Velocity 2 = 5.75 m/s