Question

1)(a) x+y+z=0,show that x^3+y^3+z^3=3xyz
(b) show that (a-b)^3 + (b-c)^3 +(c-a)^3 = 3(a-b)(b-c)(c-a)

Answer 1

Step-by-step explanation:

X + y + z = 0

Cube it on both the sides.

(x + y + z)^3 = 0^3

x^3 + y^3 + z^3 - 3xyz = 0

x^3 + y^3 + z^3 = 3xyz hence proved...