Question

(1) a2 + 4b2 + c2-4ab-4bc + 2ca
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Answer 1

Answer:

The answer is (a-2b+c)^2

Step-by-step explanation:

a2+4b2+c2-4ab-4bc+2ca

= a2+(-2b)^2+c^2+2*a*(-2b)+2*(-2b)*c+2*c*a

= (a-2b+c)^2