Question

1. ABC ~APOR, if AB=6cm; BC=4cm; AC=8cm; PR=6cm, then PQ+QR= 1) 8cm 2) 10cm 3) 7.5cm 4) 9cm
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Answer 1

by the property of similar triangle we have,

AB/PQ = BC/QR = AC /PR

6/PQ = 4/QR = 8/6

6/PQ = 4/3

PQ = 18/4

PQ = 4.5

4/QR = 4/3

12/4 = QR

QR = 3

hence,

PQ + QR = 3+4.5 = 7.5 cm