Math, asked by Sanskriti1111, 4 months ago

1. ABCD is a parallelogram. If its diagonals are equal then the value of angle ABC is ?

2. The adjacent sides of a rectangle ABCD are 8 cm and 6 cm. If E, F, G, H are the mid-points of the sides of ABCD, then the area of rhombus EFGH is

Answers

Answered by yushikagupta
0

Answer:

2) 12square.cm

Step-by-step explanation:

AB= 8cm

BD= 6cm

CD=8cm

AC= 6cm

EF= 1/2 of AB

FG= 1/2 of BD

GH= 1/2 of CD

HE= 1/2 of AC

Thus area is EF mulitipled by FG= 4 ×3= 12square cm.

Answered by Priyam117
0

Answer:

1. Either 45° or 90° - angleCBD

2. 24cm^2

Step-by-step explanation:

1. ABCD is a ||gm and its diagonals are equal that means its either a rectangle or square -

In case of a rectangle -> angleABC = 90° - angleCBD

In case of a square -> 45° since the diagonals bisecet angleA, B, C and D.

2. Area of rhombus = Product of diagonals/2

Now, EFGH is rhombus and E, F, G and H are midpoint of AB, BC, CD and DA

=> AC = EG and AB = HF

=> Area = EG × HF /2 = 6×8/2 = 48/2 = 24

(refer to the image)

NOTE: I have taken AB and AC as adjacent.

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