Question

1. ABCD is a trapezium. E is the mid-point of AD. BC
= 6 cm and EF is drawn parallel to AB. The length
of BF is-​

Answer 1

Answer:

BF = 3cm

Step-by-step explanation:

AB∥DC & EF∥DC, therefore  

   AB∥EF∥DC

Join AC which intersects EF at G. In △ABC,

AB║GF    [∵EF is the extension of FG]

$\frac{BF}{FC} = \frac{AG}{GC}$      →(1) [Lines drawn parallel to one side of triangle intersects the other two sides in distinct points. Then it is divided the other two sides in same ratio]

∴ BF = 3cm.

hope it will help you.