Question

1. Add:
a) x3 – 2x²y + 3xy2 – y3, 2x3 - 5xy2 + 3x2y - 4y3​

Answer 1

Step-by-step explanation:

Solution :-

(x^3 - 2x^2y + 3xy^2 - y^3) + (2x^3 - 5xy^2 + 3x^2y - 4y^3)

=> (1 + 2)x^3 + (-2 + 3)x^2y + (3 - 5)xy^2 + (-1 -4)y^3

=> 3x^3 + x^2y - 2xy^2 - 5y^3

Answer) 3x^3 + x^2y - 2xy^2 - 5y^3

Answer 2

Answer:

Given x3 -2x2y + 3xy2– y3, 2x3– 5xy2 + 3x2y – 4y3

Collecting positive and negative like terms together, we get

= x3 +2x3 – 2x2y + 3x2y + 3xy2 – 5xy2 – y3– 4y3

= 3x3 + x2y – 2xy2 – 5y3