Math, asked by ashwinianu9, 11 months ago

1. Amina buys a book for rs.275 and sells it at a loss of 15%. How much does she sell it for?
2. Find the amount to be paid at the end of 3 years in each case:
(a) Principal = 1,200 at 12% p.a. (b) Principal = 7,500 at 5%p.a.
3. What rate gives 280 as interest on a sum of 56,000 in 2 years?
4. If Meena gives an interest of rs.45 for one year at 9% rate p.a.. What is the sum she has borrowed?
Guys please ans these 4 questions​

Answers

Answered by sakthikeerthimvm
4
  1. CP = 275rs

loss%=15

SP = x rs

loss = CP - SP = 275-x

loss % = (275-x)/275 × 100

15 = (27500-100x)/275

4125 = 27500-100x

100x = 27500-4125

100x = 23375

x = 23375/100 => 233.75 rs

2.(a)

Principal = P = RS.1200

Rate of interest = R = 12% p.a.

Time = T = 3 years

Simple interest = PTR/100

= 1200 × 3 × 12/100

= RS.432

Therefore, amount = Principal + Interest

= RS.1200 + RS.432

= RS.1632

Ans: The amount is RS. 1632.

_____________________________________________

(b)

Principal = P = RS. 7500

Time = T = 3 years

Rate of interest = R = 5% p.a.

Simple interest = PTR/100

= 7500 × 3 × 5/100

= RS.1125

Therefore, amount = Principal + Interest

= RS. 7500 + RS.1125

= RS.8625

Ans: The amount is RS.8625.

3.SI = P×R×T/100

Rs280 = 56000×x×2/100

Rs280 = 560×2x

280/ 560 = 2x

1/2 = 2x

1/2×2=x

1/4 = x

0.25 = x

4.S.I -:45 Rs

time :- 1 year

rate :- 9%

S.I = P×R×T\100

45= P×9×1/100

P =45×100/9

P= 4500/9

P= 500 rs

Hope it helps you

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Answered by sahoorishi101
1

Answer:

Step-by-step explanation:

CP=RS-275

LOSS%=15%

SP=15% OF CP

=15/100×275

=41.25

So we will subtract the loss with the cp.

275-41.25

=233.75(ANS)

2.

a.PRINCIPAL=1200

TIME=3 YEARS

RATE % PER ANNUM=12%

ACCORDING TO THE FORMULA TO FIND SIMPLE INTREST =PRINCIPAL×RATE%×TIME

=1200×3×12/100

=432=SIMPLE INTREST

AMOUNT=SIMPLE INTREST +PRINCIPAL

A=432+1200

=1632(ANS)

2.

b.P=7500

R%=5%

T=3YEARS

SI=P×R×T

=7500×5/100×3

=1125

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