Question

1. An apple of mass 150g falls on the surface
of the earth from a negligible height (in
comparison with the radius of the earth) due
to gravitation. Calculate the gravitational force
acting between the apple and the earth. Also
calculate the acceleration produced in both of
them due to the gravitational force.
(Mass of the earth = 6 x 1024 kg and Distance
between the centre of the earth and the
ápple = 6.38 x 106m)​

Answer 1

Answer:

Gravitational Force = 1.47 N

Acceleration produced in Apple = 9.8 m/s^2

Acceleration produced in Earth = 2.45 x 10^(-23) m/s^2

Explanation:

Mass of Apple = 150 g = 0.15 Kg

Mass of Earth = 6 x 10^24 Kg

Radius of Earth = 6.38 x 10^6 m

Universal Gravitational Constant G = 6.67 x 10^-11 Nm^2/kg^2

Force due to gravity = G (mass of apple) (mass of earth) / (radius of earth)^2

We know that G (mass of earth) / (radius of earth)^2 = g = 9.8 m/s^2

So F = 9.8 (mass of apple) = 1.47 N

Gravitational Force = 1.47 N

By 2nd law of motion F = ma, a = F/m

Acceleration produced in Apple = F / (mass of apple) = 1.47 N / 0.15 Kg = 9.8 m/s^2

Acceleration produced in Earth = F / (mass of earth) = 1.47 N / 6 x 10^24 Kg = 2.45 x 10^(-23) m/s^2