Question

1. An iron ball requires 1000 J of heat +
raise its temperature by 20°C. Calculate
the heat capacity of the ball.​

Answer 1

Answer:

Given

Heat Require=1000 J

change in Temperature=20 ^{\circ}c

and we know

heat transferred is Q=C\Delta T

Where C=heat capacity

1000=C\times 20

C=50 J/^{\circ}c

Answer 2

Answer:

according to question :-

heat capacity = heat of object / change in temperature

so heat capacity = 1000/20 = 50 j/degree Celsius

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