Question

1. An olympic outdoor archery target is made up of 10 equally spaced concentric circles. If the diameter
of the biggest ring on the target is 122 cm and the diameter of the bullseye is 12.2 cm, what is the
diameter of the fourth ring from the inside?
Plz tell me it is my exam
​

Answer 1

Answer:

Step-by-step explanation:

4times the bulls eye

4(12.2)=48.8

Answer 2

Answer:

diameter of the fourth ring from the inside = 48.8 cm

Step-by-step explanation:

Let say width between two circles = d cm

Diameter of 1 st Circle = 12.2 cm

Diameter of 2nd Circle  = 12.2 + 2d  cm

Diameter of 3rd circle = 12.2 + 2d + 2d =  12.2  + 2 *2d

Diameter of 4th circle = 12.2 + 2*2d + 2d =  12.2  + 3 *2d

Similarly Diamater of 10th circle = 12.2 + 9*(2d)

12.2 + 9*(2d) = 122

=> 2d = 12.2

Diameter of 4th circle =  12.2  + 3 *2d

= 12.2 + 3 * 12.2

= 48.8 cm

diameter of the fourth ring from the inside = 48.8 cm