Question

1 and 2 are the zeros. of the polynomial, px =x2-3x+ 2​

Answer 1

Answer:

Yes, 1 and 2 are zeros of the p(x)

Step-by-step explanation:

$p(x) = x^2 -3x + 2\\p(x) = x^2 - x - 2x +2\\p(x) = x(x-1) - 2(x-1)\\p(x) = (x-1)(x-2)$

Put p(x) = 0, to find zeros

$p(x) = 0\\(x-1)(x-2) = 0\\\\x-1 = 0 \\=> x=1\\x-2 = 0\\=> x=2$

Therefore x=1 and x=2 are zeroes of the polynomial