Question

1) Area of rectangle ABCD is 36 square 1 point cm. What is the area of triangle ABP?* P B O 36 sq.cm O 18 sq.cm O 72 sq.cm O 30 sq.cm
give steps​

Answer 1

➸ Given:-

• ABCD is a rectangle & ∆ABP is inscribed in it.
• Area of Rectangle is 36cm²

➸ To Find:-

• Area of ∆ABP

ᬊ Required Response:-

WKT

If a Triangle and a Parallelogram is on the same base and between same parallels...

Then, $\bf{\star\;Area_{(Triangle)} = \frac{1}{2}[Area_{(Parallelogram)}]}$

As, We know that

Every Rectangle is a Parallelogram but all parallelograms are not rectangles.

So, In Rectangle ABCD

• AB || CD
• AD || BC

Here, ∆ABP and ▭ABCD is on the same base(AB) and between same parallels[AB || CD]

$\bf{\star\;Area_{(Triangle)} = \frac{1}{2}[Area_{(Rectangle)}]}$

$\frac{1}{2} (36) \\ \frac{1}{2} \times 36 \\ 18$

Area of ∆ABP

• $\longmapsto\;\red{\bold{18{cm}^{2}}}$

$\boxed{\tt{@MrSovereign}}$

Hope It Helps You ✌️

Answer 2

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