Question

1. Ashish travels a distance of 100 km in the following manner, at 20 kmph for
the 1st 50 kms, at 25 kmph for the next 50 kms. He returns at a constant
speed of 25kmph. What was his average speed for the journey?
ring.
(a) 22.50
(b) 23.52
(c) 24.60
(d) 22.35
​

Answer 1

Answer:

Average speed = (20 + 25 + 25)/3

= 23 km/h

Answer 2

Answer:

The average speed of Ashish for the journey is 23.52 km/h

Given:

It has been given that Ashish travels a distance of 100 km in the following manner:

• $20 \ km/hr$ for the first $50 \ km$
• $25 \ km/hr$ for the next $50 \ km$
• He returns at a constant speed of $25 \ km/hr$

To find:

We have to find out his average speed for the journey.

Solution:

To calculate the average speed, we have to go by the following method:

$time = \frac{distance}{speed}$

⇒$\frac{100+100}{\frac{50}{20}+\frac{50}{25} +\frac{100}{25} }$

⇒ $\frac{200}{2.5+2+4}$

⇒ $\frac{200}{8.5}$

⇒$23.52 \ km/hr$

Final Answer:

The average speed of Ashish for the journey is 23.52 km/h

Link:

https://brainly.in/question/29440045?referrer=searchResults

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