Question

1) Atoms of B forms hexagonal close packing and atoms of A occupies 2/3 of the tetrahedral void. What is the formula of the compound? plss answer.. anyone plss. for crct answers i ll mark it as the brainliest.

Answer 1

Answer:

CHEMISTRY

A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 many of these are tetrahedral voids?

ANSWER

Number of atoms in close packaging = 0.5 mol

1 has 6.022×10

23

particles

So that

Number of close-packed particles

=0.5×6.022×10

23

=3.011×10

23

Number of tetrahedral voids = 2 × number of atoms in close packaging

Plug the values we get

Number of tetrahedral voids =2×3.011×10

23

=6.022×10

23

Number of octahedral voids = number of atoms in close packaging

So that

Number of octahedral voids =3.011×10

23

Total number of voids = Tetrahedral void + octahedral void

=6.022×10

23

+3.011×10

23

=9.03×10

plzz mark as brainlist