Question

(1)| both charges and distance between them is doubled, then electrostatic force will be
(a)F
16) 2F
(c) zero
(d) none
(2)The electrostatic force between two like charge is
(a)attractive
b) repulsive
(c) both a and be
(d none
Tos​

Answer 1

Answer:

a) F

b) Repulsive

Explanation:

a)

1st case,

$f \: = \dfrac{q_1 q_2}{ {r}^{2} }$

2nd case,

$\frac{2q_1\: \times 2q_2}{ {(2r)}^{2} } \\ \\ = \frac{4q_1 q_2}{4{r}^{2} } \\ \\ = \frac{q_1 q_2}{{r}^{2} } = f$

b) As we know negative and positive charge attract each other this mean their electrostatic force is attractive in nature, Vice versa Electrostatic force of two like charge is repulsive in nature.