Chemistry, asked by ronitgoradkar, 3 months ago

1 bromo 2 methylpropane by action of mg in dry ether​

Answers

Answered by keyuraundhekar
0

Answer:This is the preparation and hydrolysis of a Grignard reagent.

Explanation:

Part (i)

This is the preparation of a Grignard reagent.

R-X

+

Mg

dry ether

−−−−→

R-MgX



Grignard Reagent

Your equation is

(

CH

3

)

3

C-Br

+

Mg

dry ether

−−−−→

(

CH

3

)

3

C-MgBr

Part (ii)

This is the hydrolysis of a Grignard reagent.

R-MgX

+

H

2

O

RH

+

MgX(OH)

The

R-MgX

behaves as if it were

R

,

+

MgX

.

The

R

is a strong base, so it removes a proton from the water to form

RH

.

Your equation is

(CH

3

)

3

C-MgBr

+

H

2

O

(CH

3

)

3

C-H

+

MgBr(OH)

Note: the

MgBr(OH)

is a gelatinous substance, so the hydrolysis is usually carried out in the presence of dilute acid to dissolve the basic salt.

Explanation:

Answered by aaryan03123
1

Answer:

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