Question

1-Bromopentane on boiling with alcoholic potassium hydroxide gives
a) pentan-1-ol
b) pentan-2-ol
c) pent-1-ene
d) pent-2-ene

Answer 1

the answer is pent-1-ene

Answer 2

Hey Dear,

◆ Answer -

1-Bromopentane on boiling with alcoholic potassium hydroxide gives pent-1-ene.

● Reaction -

Alkyl halides on treatment with alcoholic potassium hydroxide causes dehydrohalogenation & gives alkene.

1-Bromopropane on dehydrogenation by alc.KOH gives pent-1-ene.

CH3-CH2-CH2-CH2-CH2-Br + alc.KOH --> CH3-CH2-CH2-CH=CH2 + KBr + H2O

Hope this helps you.