Question

1 by 2 and minus 2 August zeros of polynomials 2x Cube + x square - 5 x + 2

Answer 1

Given, 1/2 and -2 are the zeros of the p(x).

So, Sum of zeros = alpha + beta

=1/2-2=-3/2

Product of zeros =alpha. beta

=1/2*-2=-1

therefore, k={(x^2-(sum of zeros)x +product of zeros) }

or, k=(2x^2+3x-2/2)

where, k=2 (real no.)

p(x)=(x+1/2)(x-2)(2x^2+3x-2)

p(x)=(x+1/2)(x-2)(x+2)(2x-1)

Therefore, the zeros of the given p(x) are:1/2,-2,-2,1/2

Answer 2

i think something is mistake in your questions
right questions is like that:-

Find the third zero of the polynomial 2 x cube - x square - 5 x minus 2 if it is given that the -1 and 2 are the two zeroes of the polynomial
its two zeroes are given

x = -1,2

(x + 1)(x - 2)

=> x² - 2x + x - 2

=> x² - x - 2

x² - x - 2)2x³ - x² - 5x - 2(2x + 1
2x³ - 2x² - 4x
(-)____(+)___(+)
—————————
x² - x - 2
x² - x - 2
(-)___(+)__(+)
—————————
0 0 0

hence the another zeroes is
2x + 1 = 0

=> x = -1/2

Hope it helps you
Please make me as brainliest