Question

1. Calculate the (a) empirical formula, and (b) molecular formula of a compound having the following percentage composition
Sodium = 42.19 phosphorus - 18.9% and oxygen 39. Given that the molecular mass of the compound 1 16
[Na = 23, P=31 and 0 = 16]​

Answer 1

Answer:

for sodium=42.19/23=1.83

Explanation:

for phosphorus=18.9/31=0.60. for oxygen=39/16=2.4

simplest molar ratio=

1.83/0.60=3.05

0.60/0.60 =1

2.4/0.60=4

slmplest whole no ratio

3.05*2 =6

1*2=2

4*2=8

empirical formula=I Na6P2O8

molecular formula=n*ef