Question

1. Calculate the amount of heat required to convert
10 g of water at 0 °C to ice at 0 °C. (Specific
latent heat of fusion = 80 cal/g)​

Answer 1

Answer:

800cal

Explanation:

if we want to convert water in ice then we have to take heat from .

so this heat will be taken as latent heat of fusion so

Q=mlf

lf=80cal/g

so

Q=10×80

=800cal