Question

1. Calculate the amount of heat required to
convert 80 g of ice at 0°C into water at the
same temperature. (Specific latent heat of​

Answer 1

Answer:

Heat = mL

Latent Heat = mL

Q = 80 × 80 = 6400cal

Q = 6400 × 4.2 = 26880Joule

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Answer 2

Answer:

heat = ml

80×80

6400 cal

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