Question

1) Calculate the no. of Sodium atoms present in 54.5g of Sodium (At. Mass of Na=23g)​

Answer 1

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Answer 2

To find:

The number of Sodium atoms in 54.5 g of Sodium?

Calculation:

First of all, let's calculate the moles of sodium in the sample:

$\sf \therefore \: moles = \dfrac{given \: mass}{atomic \: mass}$

$\sf \implies \: moles = \dfrac{54.5}{23}$

$\sf \implies \: moles = 2.36$

Now, the number of atoms can be calculated by multiplying the number of moles with Avagadro number:

$\sf \therefore \: atoms = moles \times avagdro \: number$

$\sf \implies \: atoms = 2.36 \times 6.023 \times {10}^{23}$

$\sf \implies \: atoms = 14.27\times {10}^{23}$

$\sf \implies \: atoms = 1.427\times {10}^{24}$

So, 1.427 × 10²⁴ atoms of sodium are present.