Question

1. calculate the number of electrons present in 100 gram of CaCO3 3 molecule.
2. calculate the molarity of solution when 40 gram NaOHdissolved in 500 ml of solution.​

Answer 1

Explanation:

1) no of molecules = weight / molecular mass × N*

no of molecules = 100/100 × N*

= N*

no of e- in 1 molecule = 50

total es i n N* molecules = 50 N*

= 50×6.022×10^23

2) M = W/M×1000/V

M= 40/40 × 1000/500

= 2 M

Hope it will help you.