Some nickel(ii) sulfate solution was carefully placed
in the bottom of a beaker of water. The beaker was
then covered and left for several days.
a Describe what you would see after:
(i) a few hours
(ii) several days.
b Explain your answer to a using your ideas of the
kinetic theory of particles.
c What is the name of the physical process that
takes place in this experiment?
Answers
Answered by
5
Solution:- (A) 7.8g
Decomposition of CaCO
3
-
CaCO
3
⟶CaO+CO
2
At STP,
22.4L of a gas =1 mole
Therefore,
1.12L of CO
2
=
22.4
1
×1.12=0.05 mole
From the above reaction,
1 mole of CO
2
is produced by 1 mole of CaCO
3
.
0.05 mole of CO
2
will be produced by 0.05 mole of CaCO
3
.
Therefore,
Molar mass CaCO
3
=100g/mol
Mass of 0.05 mole of CaCO
3
=0.05×100=5g
Now, again from the above reaction,
Molar mass of CaO=56g/mol
100g of CaCO
3
gives 56g of CaO.
5g of CaCO
3
will give
100
56
×5=2.8g
Therefore,
Total mass residue =5+2.8=7.8g
Hence the mass of residue left is 7.8g.
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