1)calculate the thrust exerted by a block of mass 50g
2)find the pressure exerted by a cubical block of side 10cm and mass 400g when placed on a table top
3)a rectangular iron block of mass 10g and dimensions 20cm*10cm*5cm is placed on a table. find the pressure exerted by a block on the table if the block lies on the table with dimensions
I)20cm*10cm and ii)10cm*5cm
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1. 50g= 0.05 kg
=》 thrust( perpendicular force) = ma
= 0.05× 10=0.5N
2. length = 10cm= 0.1m
mass = 400g= 0.4kg
P=F/A
=》 P= (0.4×10)/0.1
=4/0.1
=40Pa
3. i) mass= 10g= 0.01 kg
length= 20cm=0.2m
width= 10cm=0.1m
=》 area of base= 0.2×0.1
=0.02m^2
=》 P= F/A
=》 P= (0.01×10)/0.02
= 0.1×0.02
= 0.002Pa
ii)width= 10cm=0.1m
length= 5cm=0.05m
Area of base= 0.1×0.05= 0.005m^2
=》 P= 0.1/0.005 ( force is given in the previous part)
= 20Pa
=》 thrust( perpendicular force) = ma
= 0.05× 10=0.5N
2. length = 10cm= 0.1m
mass = 400g= 0.4kg
P=F/A
=》 P= (0.4×10)/0.1
=4/0.1
=40Pa
3. i) mass= 10g= 0.01 kg
length= 20cm=0.2m
width= 10cm=0.1m
=》 area of base= 0.2×0.1
=0.02m^2
=》 P= F/A
=》 P= (0.01×10)/0.02
= 0.1×0.02
= 0.002Pa
ii)width= 10cm=0.1m
length= 5cm=0.05m
Area of base= 0.1×0.05= 0.005m^2
=》 P= 0.1/0.005 ( force is given in the previous part)
= 20Pa
Adiboi:
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