Question

1. Calculate the value of the acceleration due to gravity at a place 3,200 km above the surface of the earth. (ME=6 x 1024 kg, RE= 6400km)​

Answer 1

Assume-

h= 3200km = 3200000m = 3.2 x10^6

R= 6400km = 6400000m = 6.4 x 10^6

g= 9.8m/s^2

We know that-

g'= g[R^2/(R+h)^2]

= 9.8(40.96 x 10^12/92.16 x 10^12)

= 9.8 x 4/9

= 4.355m/s^2 ~ 4.4m/s^2

Thus, value of g at a place 3200km above surface of the earth is 4.4m/s^2.