Math, asked by aniketgautamas1023, 1 month ago

1. Cards marked with the numbers 2 to 101 are placed in a
box. One card is drawn at random. Find the probability that
the card drawn bears a number which is a perfect cube. ​

Answers

Answered by sethrollins13
93

Given :

  • Cards marked with the numbers 2 to 101 are placed in a box.

To Find :

  • Probability of getting a card that bears a number which is a perfect cube.

Solution :

\longmapsto\tt{Total\:Outcomes=100}

\longmapsto\tt{Favourable\:Outcomes=3}

8,27,64

Using Formula :

\longmapsto\tt\boxed{Probability=\dfrac{No.\:of\:Fav.\:Outcomes}{Total\:no.\:of\:Outcomes}}

Putting Values :

\longmapsto\tt\bf{\dfrac{3}{100}}

So , The Probability of getting a perfect cube is 3/100 .

_______________________

Probability :

It is defined as chances of occuring or happening of an event.

  • Probability of an event can never be negative.
  • Probability of an event always lies between 0 and 1.

_______________________

Answered by MяMαgıcıαη
74

\LARGE\boxed{\textsf{\textbf{Given\::-}}}

\:

  • Cards marked with the numbers 2 to 101 are placed in a box.

  • One card is drawn at random.

\:

\LARGE\boxed{\textsf{\textbf{To\:Find\::-}}}

\:

  • Probability that the card drawn bears a number which is a perfect cube ?

\:

\LARGE\boxed{\textsf{\textbf{Solution\::-}}}

\:

\Large\underbrace{\underline{\sf{How\:to\:solve\:::}}}

\:

  • We clearly know that, between 2 and 101 there are 3 perfect cubes i.e, 8, 27 and 64. 8 is cube of 2, 27 is cube of 3 and 64 is cube of 4. So, favorable outcomes = 3 and total number of outcomes = 100. So, let's solve it by using well known formula ::

  • \boxed{\bf{Probability = \dfrac{Favourable\:outcomes}{Total\:number\:of\:outcomes}}}

\:

\underline{\sf{\bigstar\:Putting\:all\:known\:values\:::}}

\\ \longrightarrow \:\bf Probability_{(getting\:a\:perfect\:cube)} = \dfrac{3}{100}

\:

  • Therefore, probability of getting a perfect cube is 3/100.

\:

\LARGE\boxed{\textsf{\textbf{Explore\:More\::-}}}

\:

  • Probability of any event can't be negative. It always lie between 0 and 1.

\:

L e a r nm o r eonbrainly

\:

\underline{\sf{\bigstar\:Question\:::}}

\:

There are six red marbles 4 green and 2 white marbles in a box what is the probability of drawing a non white marble

\:

\underline{\sf{\bigstar\:Answer\:::}}

\:

https://brainly.in/question/40134750

\:

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