Question

1 cc of 0.1 n hcl is added is added to 99 cc of nacl . what will be the ph of the resulting solution

Answer 1

Data:
Volume of HCL = 1 cm³ = 1/1000 = 0.001 L
Volume of NaCl = 99 cm³ = 99/1000 = 0.099 L
Normality of HCL = 0.1 N
pH of the resulting solution = ?
Solution:
Normality volume = (0.1) (0.001)
Normality volume = 0.0001 L
Volume of solution = Volume of NaCl + Volume of HCL
Volume of solution = 1 + 0.001
Volume of solution = 1.001 L
Since NaCl is a salt and is neutral so it does not effect pH of a solution.
Now,
Normality of HCL in a resulting solution = 0.0001 / 1.001
Normality of HCL in a resulting solution = 0.0001 N
So,
pH = - log [H⁺]
pH = - log (0.0001)
pH = 4
which shows that the pH of the resulting solution is 4
Hope it helps. Thanks.

Answer 2

Answer:

pH = 4

Step-by-step explanation:

see the photo hope it help