Question

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

Answer 1

capacity of (6men+8boy) in 10 days =capacity of (26men+48boys) in 2days
hence ,
10 (6men +8boys)=2 (26men+48boys)
=> 60men+80boys =52men +96boys
=> 8men =16boys
=> 1 men=2boys
so,
(6men +10boys )=(12boys + 10boys)=22boys do work 10days
hence 1 boy does work 10x 22 =220days

now ,
15men+20boys =30boys +20boys
=50boys
because 1boy does work =220day
so, 50boys do work=220/50 days
=4.4 days
hence (15men+20boys) do work 4.4 days

Answer 2

Easy trick method please solve this question