Question

A batsman deflects a ball by an angle 45 degrees without changing its initial speed which is equal to 54 km/hr . what is the impulse imparted to the ball? Mass of the ball is 0.15kg.

Answer 1

Answer:

Impulse = $4.16 kg m s^{-1}$

Explanation:

In this question

The ball struck by the bat is defected back such that total angle is 45° .

Now, initial moment of ball = $m\times u\times cos\Theta$

                         = $\frac{15\times 54\times 1000\times cos(22.5)}{3600}$

                        = $0.15\times 15\times 0.9239$  along NO

Final momentum of ball = $m\times u\times cos\Theta$  along ON

Impulse = change in momentum

             = $m\times u\times cos\Theta - (-m\times u\times cos\Theta)$

             = 2$m\times u\times cos\Theta$

              = 2$0.15\times 15\times 0.9239$

Impulse =$4.16 kg m s^{-1}$