Question

two circles intersect each other at point A and B . AP and AQ are diameter of the two circles respectively.if angle APB=40 degree.and angle AQB=70 degree find angle pab and angle qab.

Answer 1

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Answer 2

Angle pab=50 degree and angle qab=20 degree.

Step-by-step explanation:

Given:

As shown in figure below, let two circles C(O, r) and C(O',r') with AP and AQ as diameters, intersecting at A and B.

∠APB= 40° and ∠AQB=70°

As, we know that an angle in a semicircle=90°.

∠ABP=90°  and ∠ABQ=90°  

Now,  In ΔABP,

∠ABP+∠BPA+∠PAB=180°

90°+40°+∠PAB=180°

∠PAB=180°-130°

∠PAB=50°

And  in ΔABQ,

∠ABQ+∠BQA+∠QAB=180°

90°+70°+∠QAB=180°

∠QAB=180°-160°

∠QAB=20°