Question

1 CC of oxygen at NTP contains

Answer 1

$\textbf{\huge{\underline{ Hello Mate! }}}$

$\textsf{\red{ Since, 1 cubic cm = 1 milileter. }}$

Now, we know that 1 milileter = $10^{-3} l$

In NTP conditions, 1 mole = 22.4 liters

So, 22.4 liter contain = 1 mole of O2

1 liter contain = 1 / 22.4 mole of O2

${10}^{ - 3} \: liter \: contain = \frac{ {10}^{ - 3} }{22.4} \: moles \\ = \frac{1}{1000} \times \frac{1}{22.4} \\ = 0.00004 \: or \: 4 \times {10}^{ - 5} \: moles$

$\textbf{ Have great future ahead! }$