1. Certain force acting on a 20 kg mass changes its velocity from
5 ms-1 to 2 ms-1. Calculate the work done by the force.
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Kinetic energy is given by the expression, (E k) v = 1/2 mv^2
Where,
E k= Kinetic energy of the object moving with a velocity, v
(i) Kinetic energy when the object was moving with a velocity 5 m s-1
(E k)5 = 1/2 — 20 — (5)2 = 250 J
Kinetic energy when the object was moving with a velocity 2 m s-1
(E k)2 = (1 )/2x 20 — (2)2 = 40 J.
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Answer:
Kinetic energy is given by the expression, (E k) v = 1/2 mv^2
Where,
E k= Kinetic energy of the object moving with a velocity, v
(i) Kinetic energy when the object was moving with a velocity 5 m s-1
(E k)5 = 1/2 — 20 — (5)2 = 250 J
Kinetic energy when the object was moving with a velocity 2 m s-1
(E k)2 = (1 )/2x 20 — (2)2 = 40 J.
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