Question

4. Archana starts journey from Delhi at 8 a.m. for Jaipur. Her car is running at a
speed of x km/h. If at 1 p.m., she observes that she is 20 km away from Jaipur, find
the distance between Delhi and Jaipur.
(Hint: Distance = speed x time)​

Answer 1

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

So by this property:

∠A+∠B=∠ACD

⟹∠A+40

∘

=120

o

∠A=120

o

−40

o

=80

o

.

Answer 2

Step-by-step explanation:

Given:-

Archana starts journey from Delhi at 8 a.m. for Jaipur. Her car is running at a speed of x km/h. If at 1 p.m., she observes that she is 20 km away from Jaipur.

To find:-

find the distance between Delhi and Jaipur.

Solution:-

Starting point of Archana's journey from Delhi

=8 am

Ending time of Archana's journey to Jaipur =1pm

Time taken by Archana for the journey from Delhi to Jaipur = 5 hours

(8-9,9-10,10-11,11-12,12-1= 5 hours)

Speed of the car = x km/hr

The distance travelled by her from Delhi to Jaipur =

Time taken for the journey× speed of the car

=>D=5x km

and she observes that she is 20 km away from jaipur

So total distance she travelled = 5x+20 km

Answer:-

Total distance is (5x+20 ) km