Question

1. Check whether 12n can end with digit 0 for any natural number N​

Answer 1

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• Here, Number 12n where nϵN
• Now 12²=(2 x 3)n

• Now, for 12 n to end with 0, it should have 2 as well as 5 in its prime factors. Also to end with 5, of require at least a single multiple of 5 in its prime factors, so 12 n
• cannot end with the digit 0 or 5.

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⫷MARK AS BRAINLEAST⫸