Question

The perimeter of the rectangle and square are same .Length and breadth of the rectangle are 10 cm and 8 cm respectively. What is the area of the
square.​

Answer 1

$\huge{❥}\:{\mathtt{{\purple{\boxed{\tt{\pink{\red{A}\pink{n}\orange{s}\green{w}\blue{e}\purple{r᭄}}}}}}}}$

Given:-

Length and breadth of the

rectangle are 10 cm and 8 cm, perimeter

of the rectangle and square are same.

To find:-

area of the square=?

Solution:-

So, we have given that perimeter of rectangle and square are same and length and breadth of the rectangle is also given.so first we need to find the perimeter of the rectangle.

Perimeter of rectangle is = 2(+b)

=2(10+8)

=2(18)

= 36 cm.

Now, perimeter of square is 4(a),

where a is the side of square.

We have given that perimeter is

equal so equate 4(a) with the

perimeter of the rectangle, we get:

4(a) = 36

a = 9 cm

So the side of the square is 9cm.

Now area of sqare is 9×9=81.

Answer:-

So the area of the square is

81 cm².

Answer 2

Answer:

$\boxed{\text{So the area of the square is 81 cm².}}$

Explanation:

Given:-

Length and breadth of the

rectangle are 10 cm and 8 cm, perimeter

of the rectangle and square are same.

To find:-

$\red{area \: \: of \: \: the \: \: square}$

Solution:-

First we need to find the perimeter of the rectangle.

$\underline{ \sf \: Perimeter \: \: of \: \: \: rectangle \: \: is = \: \: 2(+b)}$

=2(10+8)

=2(18)

= 36 cm.

$\underline{ \sf \: Now, perimeter \: \: of \: \: square \: \: is \: \: 4(a),}$

where a is the side of square.

We have given that perimeter is equal so equate 4(a) with the Perimeter of the rectangle, we get:

4(a) = 36

a = 9 cm

So the side of the square is 9cm.

Now area of sqare is 9×9=81.

Answer:-

So the area of the square is 81 cm².