Question

1 cm of main scale if vernier callipers is divided into 10 divisions.least count is 0.05.how many divisions should it have​

Answer 1

Answer:

• The main scale and the vernier calliper is of 1 cm.
• There are 10 divisions in vernier calliper.
• The least count is 0.05.

Find the number of divisions should it have. (Let x)

The least count = (The difference of the number of divisions in the main scale ÷ number of divisions) * value of each division.

If there are 10 divisions in the scale of 1 cm.

Then, each division is equal to 0.1 cm.

Hence, The least count = (10 - x/10) * 0.1

= 10 - x/10 * 1/10

= 10 - x/100

Now, we are given the least count as 0.05.

Hence, 0.05 = 10 - x/100

So, 0.05 * 100 = 10 - x

Solving further,

5 = 10 - x

- x = 5 - 10

- x = - 5

x = 5

Hence, the number of divisions in the main scale = 5.

Answer 2

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QUESTION :

1 cm of main scale if vernier callipers is divided into 10 divisions.

The least count is 0.05.

How many divisions should it have?

SOLUTION :

In the above Question, we have the following information provided :

The least count is 0.05

In 1 cm, it is divided into 10 divisions.

So, 1 division takes :

1 / 10 cm

=> 0.1 cm.

So each one division takes 0.1 cm.

Let the number of divisions be D.

Least Count :

[ ∆ Divisions / No of division ] × Value of each division.

So,

=> { 10 - D / 10 } × { 1 / 10 } = 0.05

=> 10 - D / 100 = 0.05

=> 10 - D = 5

=> D = 5

So the number of divisions it should have is 5

ANSWER :

The vernier scale should have 5 divisions.