Math, asked by sunilnsn0, 8 months ago

Find the area of triangle having perimeter 32 cm, one
side is 11 cm and defference of other two sides is 5 cm​

Answers

Answered by NaffyDharni
7

Answer:

66

Step-by-step explanation:

Perimeter = 32cm,

side a = 11 cm,

side b = xcm,

side c = x-5cm,

perimeter =sum of all sides

32 = 11 +x+x+5

32 = 16 +2x

32/16 = 2x

2/2 = x

x = 1

side b = x = 1,

side c = x+5 = 6

area of triangle = side * side * side

= 11 * 1 * 6

answer = 66

please mark my answer as the brainliest

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