Math, asked by keyaraa, 10 months ago

√1-coA whole upon √1+cosA = CosecA - cotA

Answers

Answered by Anonymous

1

Answer:

Step-by-step explanation:

[(1-cosA)/(1+cosA)]^1/2=cosecA-cotA

LHS

multiply above and below by (1-cosA)^1/2

=(1-cosA)/(1-cos^2A)^1/2

=(1-cosA)/sinA

=1/sinA - cosA/sinA

=cosecA - cotA , proved

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