1.CONSIDER AN ARITHMETIC SEQUENCE WHOSE 7TH TERM34 AND 15TH TERM IS 66.FIND THE 20T TERM.
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Answer:
86
Step-by-step explanation:
T7=a+(n-1)d;= a+6d=34; a=34-6d
(derivating this expression in T15 equation)
T15=66=a+14d;
=34-6d+14d;= 34+8d=66;
So; d=4
(now using this value to find 'a')
a=34-6d;= a=34-24 =10
So;
T20= a + 19d ;= 10 + 76
=86
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